Answer:
Final cost = $ 1313
Explanation:
Solution:-
- The order details for number of loaves for each type of bread are as follows:
{ 400 whole wheat , 200 oat bread . 350 rye bread }
- The cost per hour of mixing, baking, and packaging is as follows:
{ $ 14 , $ 25 , $ 2 }
- The time taken in hours for making each bread in terms of mixing, backing and packaging is given in a form of matrix:
![A = \left[\begin{array}{cccc}Mix&Bake&Package\\0.04&0.07&0.02&Wheat\\0.03&0.05&0.02&Oat\\0.04&0.06&0.02&Rye\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/high-school/m2t34jeco3baygn08mdexqvsa1v2vpqe6g.png)
- We will define matrix B as the number of each bread on order. Such that AB gives us the time taken for making order:

- The product of two matrix AxB would be:
![A*B = \left[\begin{array}{cccc}Mix&Bake&Package\\0.04&0.07&0.02&Wheat\\0.03&0.05&0.02&Oat\\0.04&0.06&0.02&Rye\end{array}\right] x \left[\begin{array}{ccc}400\\200\\350\end{array}\right] = \left[\begin{array}{ccc}37\\29\\35\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/high-school/ciy7enlpderg4bkjh5qoz1x09abpcr02en.png)
- The matrix C representing the rates:
![C = \left[\begin{array}{ccc}14&25&2\end{array}\right]](https://img.qammunity.org/2021/formulas/mathematics/high-school/r0yajz2nbg2fy5scsw9zta1ssqixgs6fgd.png)
- The final cost would be:
![\left[\begin{array}{ccc}14&25&2\end{array}\right] x \left[\begin{array}{ccc}37\\29\\35\end{array}\right] = 1313](https://img.qammunity.org/2021/formulas/mathematics/high-school/duis5zwb2mprpqvcjmbf4wg2447qdiwler.png)
Final cost = $ 1313