Question

The reaction of hydrochloric acid (HCl) with ammonia (NH3) is described by the equation:

HCl + NH3 → NH4Cl


A student is titrating 50 mL of 0.32 M NH3 with 0.5 M HCl. How much hydrochloric acid must be added to react completely with the ammonia?


A. 6.4 mL

B. 16.0 mL

C. 32.0 mL

D. 50.0 mL

Answer 1

Answer : The correct option is, (C) 32.0 mL

Explanation :

Formula used :

`M_1V_1=M_2V_2`

where,

`M_1\text{ and }V_1` are the initial molarity and volume of NH₃.

`M_2\text{ and }V_2` are the final molarity and volume of HCl.

We are given:

`M_1=0.32M\\V_1=50mL\\M_2=0.5M\\V_2=?`

Now put all the given values in above equation, we get:

`0.32M* 50mL=0.5M* V_2\\\\V_2=32.0mL`

Hence, the volume of hydrochloric acid added to react completely with the ammonia must be, 32.0 mL