Question

Calculate the number of moles of sodium chloride (NaCl) formed if 0.345

moles of calcium chloride (CaCl2) react.


1 Na2CO3 (aq) + 1 CaCl2 (aq) – 1 CaCO3 (s) + 2 NaCl (aq)


= ________ Moles ?

Answer 1

Answer : The number of moles of
`NaCl` formed are, 0.69 moles.

Explanation : Given,

Moles of
`CaCl_2` = 0.345 mol

Now we have to calculate the moles of
`NaCl`

The balanced chemical equation is:

`1Na_2CO_2(aq)+1CaCl_2(aq)\rightarrow 1CaCO_3(s)+2NaCl(aq)`

From the balanced reaction, we conclude that

As, 1 mole of
`CaCl_2` react to give 2 moles of
`NaCl`

So, 0.345 mole of
`CaCl_2` react to give
`2* 0.345=0.69` mole of
`NaCl`

Therefore, the number of moles of
`NaCl` formed are, 0.69 moles.