Question

A) tan
B) tan^2
C) 1
D) -1

Answer 1

A)
`\tan \theta`

Explanation:

`\frac{\sin \theta}{ \sqrt{1 - { \sin}^(2) \theta } } \\ \\ = \frac{\sin \theta}{ \sqrt{ { \cos}^(2) \theta } } \\ \\= \frac{\sin \theta}{{ { \cos} \theta } } \\ \\ = \tan \theta`