Question

Suppose 30 grams of NaCl are placed in 900 mL of water. What is the molarity of this solution?

Answer 1

Molarity= 0.57M

Step-by-step explanation:

Mm= 58.5, V= 900ml= 0.9dm3

n= m/Mm = C×V

30/58.5= C× 0.9

C= 0.57M