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A rectangle has an area of x^2-11x+30 and the length of x-5. What is the width?

User Ray Foss
by
4.5k points

2 Answers

4 votes

Answer:

x - 6

Explanation:

A = x² - 11x + 30

= x² - 5x - 6x + 30

= x(x - 5) - 6(x - 5)

= (x - 6)(x - 5)

A = L x W

W = A/L

= (x - 6)(x - 5)/(x - 5)

= (x - 6)

User Capu
by
4.1k points
4 votes

Answer:

x - 6

Explanation:

A = L x W

A / L = W

x^2-11x+30 / x -5 = W (Simplify the numerator)

(x - 6) x ( x - 5) / x - 5 = W (Cancel the similar ones which is (x - 5) )

x - 6 = W

Hope that helps

User Erken
by
4.2k points