68.1k views
4 votes
What is the molar solubility of zinc oxalate ( ZnC204) in water? The solubility-

product constant for ZnC04 is 2.7 x 10-8 at 25°C.

O

1.4 x 10-8

O 7.57

5.4 x 10-8

1.6 x 10-4

2.3 x 10-4

Question 12.11 noint)

1 Answer

3 votes

Answer:

S = 1.6 E-4 M

Step-by-step explanation:

  • ZnCO4 ↔ Zn2+ + CO42-

S S S

∴ Ksp = 2.7 E-8 = [Zn2+]*[CO42-]

⇒ Ksp = (S)*(S) = S² = 2.7 E-8

⇒ S² = 2.7 E-8

⇒ S = √2.7 E-8

⇒ S = 1.6432 E-4 M ≅ 1.6 E-4 M

User BrettAHale
by
5.0k points