Question

How many moles of oxygen must be in a 10.0 L container to exert a pressure of

0.844 atm at a temperature of 25.0 °C?*

Answer 1

0.345 mol

Step-by-step explanation:

We can solve this problem by using the equation of state for an ideal gas, which is

`pV=nRT`

where

p is the pressure of the gas

V is its volume

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

For the oxygen in this problem we have:

V = 10.0 L is the volume

p = 0.844 atm is the pressure

`R=0.082 atm\cdot L/(mol \cdot K)` is the gas constant

`T=25.0C+273=298 K` is the absolute temperature of the gas

Solving for n, we find the number of moles:

`n=(pV)/(RT)=((0.844)(10.0))/((0.082)(298))=0.345 mol`