Question

Hello people ~
please help me with thie question attached above.
Thanks in advance!​

Answer 1

Let's see

`\\ \rm\rightarrowtail W=P\vec{E}(cos\theta_i-cos\theta_f)`
`\\ \rm\rightarrowtail W=P\vec{E}(cos0-cos60)`

`\\ \rm\rightarrowtail W=P\vec{E}(1-1/2)`

`\\ \rm\rightarrowtail W=\frac{P\vec{E}}{2}`

Answer 2

W = 1/2 x P x E

Step-by-step explanation:

Let :

• P = electric dipole moment
• E = uniform electric field
• α = initial angle
• β = final angle

Formula

• The work done in a electric field can be found using the formula :
• W = P x E x (cosα - cosβ)

Solving

• W = P x E x (cos0° - cos60°)
• W = P x E x (1 - 1/2)
• W = 1/2 x P x E