Question

What volume of nitrogen gas (N2) is equal to 3.42x1022 molecules of this substance?

Answer 1

1.27

Step-by-step explanation:

Answer 2

Answer : The volume of nitrogen gas equal to
`3.42* 10^(22)` molecules of this substance is, 1.27 liters.

Explanation :

First we have to calculate the moles of nitrogen gas.

As,
`6.022* 10^(23)` molecules present in 1 mole of nitrogen gas

So,
`3.42* 10^(22)` molecules present in
`(3.42* 10^(22))/(6.022* 10^(23))=0.0568`mole of nitrogen gas

Now we have to calculate the volume of nitrogen gas.

As we know that, 1 mole of substance occupies 22.4 L volume of gas at STP.

As, 1 mole of nitrogen gas occupies 22.4 L volume of nitrogen gas

So, 0.0568 mole of nitrogen gas occupies
`0.0568* 22.4=1.27L` volume of nitrogen gas

Therefore, the volume of nitrogen gas equal to
`3.42* 10^(22)` molecules of this substance is, 1.27 liters.