Question

Solve for xxx. Write the smaller solution first, and the larger solution second. x^2 + 9x + 18 = 0x 2 +9x+18=0x, squared, plus, 9, x, plus, 18, equals, 0 \text{smaller }x =smaller x=start text, s, m, a, l, l, e, r, space, end text, x, equals \text{larger } x =larger x=start text, l, a, r, g, e, r, space, end text, x, equals

Answer 1

x = -6 or x = -3

Explanation:

x² + 9x + 18 = 0

(x + 3) (x + 6) = 0

x = -6 or x = -3

Answer 2

To solve the quadratic equation x^2 + 9x + 18 = 0, you'll have to find values of x that satisfy this equation.

To find the roots of the quadratic equation, we use the formula x = [-b±sqrt(b^2 -4ac)]/2a, where a, b, c are the coefficients of the quadratic equation of the form: ax^2 + bx + c = 0.

In our equation, we have:
a = 1 (coefficient of x^2)
b = 9 (coefficient of x)
c = 18 (constant term)

Substituting these values in our formula, we get:

x = [-9±sqrt((9)^2 - 4*1*18)] / 2*1,
x = [-9±sqrt(81 - 72)] / 2,
x = [-9±sqrt(9)] / 2,
x = [-9±3] / 2.

From here, we get two solutions:

For the smaller solution, we have: x = [-9 - 3] / 2 = -6.

For the larger solution, we have: x = [-9 + 3] / 2 = -3.

So, the solutions to the equation x^2 + 9x + 18 = 0 are x = -6 (for the smaller solution), and x = -3 (for the larger solution).