Question

Hence solve for x and y the simultaneous equations: log2x + 2log4y =4

log10( x + y ) =1

Answer 1

X = 2 and 8

Y = 2 and 8

Explanation:

Given the simultaneous equation,

log2x + 2log4y =4 ...(1)

log10( x + y ) =1...(2)

find the solution attached.