Hence solve for x and y the simultaneous equations: log2x + 2log4y =4 log10( x + y ) =1

asked Feb 15, 2021 228k views

3 votes

Hence solve for x and y the simultaneous equations: log2x + 2log4y =4

log10( x + y ) =1

5.0k points

Please log in or register to add a comment.

4 votes

Answer:

X = 2 and 8

Y = 2 and 8

Explanation:

Given the simultaneous equation,

log2x + 2log4y =4 ...(1)

log10( x + y ) =1...(2)

find the solution attached.

Aniri answered Feb 21, 2021

by Aniri

3.4k points

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

4.5m questions

5.8m answers