Question

3. The weight of cell phones is normally distributed. The mean weight of a sample of 300 cell phones is 112 grams, with a standard deviation of 2 grams. With a 95% confidence level, determine

the maximum error of estimate
18.99%
22.63%
1.31%
29.73%

Answer 1

To determine the maximum error of estimate with a 95% confidence level, we can use the formula: E = z * (sigma / sqrt(n)). Substituting the given values into the formula, we get E ≈ 0.2263 grams.

Step-by-step explanation:

To determine the maximum error of estimate with a 95% confidence level, we can use the formula:

E = z * (sigma / sqrt(n))

where E is the maximum error of estimate, z is the z-score corresponding to the confidence level (1.96 for a 95% confidence level), sigma is the standard deviation, and n is the sample size.

Substituting the given values into the formula, we get:

E = 1.96 * (2 / sqrt(300))

E = 1.96 * 0.1155

E ≈ 0.2263

The maximum error of estimate is approximately 0.2263 grams, so the correct answer is 22.63%.

Answer 2

The weight of cell phones is normally distributed. The mean weight of a sample of 300 cell phones is 112 grams, with a standard deviation of 2 grams. With a 95% confidence level, determine

the maximum error of estimate

Answer:

29.73%