Question

You are wrapping a gift with the dimensions shown below. What is the least amount of wrapping paper you need?

Answer 1

2 identical side rectangle

2 identical end triangle

1 bottom rectangle

area of trialge=1/2bh

aera of rectangle=legnth tiems width

2 side rectangles are 5 by 10=50

times 2 since 2 of them 50*2=100

end triangles

1/2 times 8 times 3=12

2 of them

12 times 2=24

bottom

8 by 10

80

add everybody

100+24+80=204 in^2 i think this is how

Explanation:

Answer 2

Answer:2 identical side rectangle

2 identical end triangle

1 bottom rectangle

area of trialge=1/2bh

aera of rectangle=legnth tiems width

2 side rectangles are 5 by 10=50

times 2 since 2 of them 50*2=100

end triangles

1/2 times 8 times 3=12

2 of them

12 times 2=24

bottom

8 by 10

80

add everybody

100+24+80=204 in^2 i think this is how

Explanation: