Question

Suppose AC = 5 cm, BC = 12 cm, and mAC = 45.2°.

To the nearest tenth of a unit, the radius of the circumscribed circle
is __?__ cm and m∠OAC = __?__°.


Help pls

Answer 1

Explanation:

Answer 2

9514 1404 393

Answer:

• 6.5 cm
• 67.4°

Explanation:

AB is shown as a diameter, which means that inscribed angle C is a right angle. The length of the diameter can be found from the Pythagorean theorem to be ...

AB^2 = AC^2 + BC^2

AB = √(5^2 +12^2) = 13

The radius is half the length of the diameter, so is ...

OA = 13 cm/2 = 6.5 cm . . . . radius

__

The measure of inscribed angle B is half the measure of arc AC, so is ...

∠B = 45.2°/2 = 22.6°

The measure of angle OAC is the complement of this, so is ...

∠OAC = 90° -22.6°

∠OAC = 67.4°