Answer:
781250 Square Meters
Explanation:
Let the dimensions of the rectangular plot be x and y
Farmer Ed wants to enclose three sides of a rectangular plot with a fencing of 2500 meters.
Therefore: Perimeter, P=x+2y=2500
We want to find the largest area that can be enclosed.
Area of the plot, A(x,y)=xy
Substitute x=2500-2y
A(y)=(2500-2y)y
![A(y)=2500y-2y^2](https://img.qammunity.org/2021/formulas/mathematics/college/1krvt8rt3ghjatg98nzwa21lnkuksjawj3.png)
To maximize A, we first find its derivative
![A'(y)=2500-4y\\$Setting A'=0\\2500-4y=0\\2500=4y\\y=625 meters\\Recall: x=2500-2y\\x=2500-2(625)=1250meters](https://img.qammunity.org/2021/formulas/mathematics/college/i7pekjhsqqy3kjqvobm3tffl5fl3dhjz3z.png)
The largest area that can be enclosed(at x=1250m,y=625m) is:
1250 X 625
=781250 Square Meters