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Determine the zeros & the y-intercept of the function 3(x-3)(x-2)

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Answer:

see explanation

Explanation:

Given

y = 3(x - 3)(x - 2)

To find the x- intercepts, let y = 0, that is

3(x - 3)(x - 2) = 0

Equate each factor to zero and solve for x

x - 3 = 0 ⇒ x = 3

x - 2 = 0 ⇒ x = 2

Thus the x- intercepts are x = 2 and x = 3

To find the y- intercept let x = 0 and equate for y, that is

y = 3(0 - 3)(0 - 2) = 3(- 3)(- 2) = 3 × 6 = 18

Thus the y- intercept is y = 18

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