Question

In a Young's double-slit experiment, light of wavelength 500 nm illuminates two slits which are separated by 1 mm. The separation between adjacent bright fringes on a screen 5 m from the slits is:______a. 0.10 cm b. 0.25 cm c. 0.50 cm d. 1.0 cm e. none of the above

Answer 1

b. 0.25cm

Step-by-step explanation:

You can solve this question by using the formula for the position of the fringes:

`y=(m\lambda D)/(d)`

m: order of the fringes

lambda: wavelength 500nm

D: distance to the screen 5 m

d: separation of the slits 1mm=1*10^{-3}m

With the formula you can calculate the separation of two adjacent slits:

`\Delta y=((m+1)(\lambda D))/(d)-(m\lambda D )/(d)=(\lambda D)/(d)\\\\\Delta y=((500*10^(-9)nm)(5m))/(1*10^(-3)m)=2.5*10^(-3)m=0.25cm`

hence, the aswer is 0.25cm