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A thin copper rod that is 1.0 m long and has a mass of 0.050 kg is in a magnetic field of 0.10 t. What minimum current in the rod is needed in order for the magnetic force to cancel the weight of the rod?
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A thin copper rod that is 1.0 m long and has a mass of 0.050 kg is in a magnetic field of 0.10 t. What minimum current in the rod is needed in order for the magnetic force to cancel the weight of the rod?

User Funky Dude
by
5.5k points

1 Answer

3 votes

Answer:

Current is 5Amperes

Step-by-step explanation:

Given length L=1m,mass M=0.05kg, magnetic field B= 0.10T since it's minimum sin90°= 1

Note

ILBsin#=mg

We're Current I= mg/LBsin#

I=0.05*10/1*0.10=5Amperes

User Ted Hosmann
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5.2k points
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