Answer:
9.36g of CaF2 is presnt in the solution.
Step-by-step explanation:
CaF2 molar concentration is 0.15mol in 1.25l of solution.
1. Convert this to the standard concentration in mol/dm3:
1dm3 = 1 L
0.15mol = 1.25 dm3
x =1 dm3
0.15 = 1.25 x
x = 0.15/1.25
x = 0.12 mol/dm3
2. Calculate the relative molecular mass of CaF2
Ca= 40, F =19
RMM = 40 + 19 *2
RMM = 40+ 38
RMM = 78g/mol
3. Calculate the concentration in g/dm3
conc. in mol/dm3 = conc in g/dm3 / RMM
conc in g/dm3 = conc in mol/dm3 * RMM
= 0.12mol/dm3 * 78g/mol
= 9.36 g/dm3
So therefore, 9.36g of CaF2 is presnt in the solution.