Question

Can you help me with this question?

Answer 1

Area=42 ft.²

Explanation:

This is an area problem. But since there are multiple shapes (2 triangles and a rectangle) we have to split the shapes and work each one separately. First we will start on the far right, with the small triangle. This one is the easiest one since the line is already drawn to separate it from the rest of the shape.

Area of a triangle=1/2 bh

A=1/2(2x3)

A=1/2(6)

A=3

The next shape is the the rectangle in the middle. Looking at the first image, I've drawn a line across the bottom, we need to find the area of that new image, the width is 3 ft and the length is 11 ft.

Area of a rectangle=lw

A=(11x3)

A=33

Finally, we need to find the area of the last triangle. Looking at the second image, I've add the correct base and height, 4 and 3. So now we need to use the triangle formula and solve

Area of a triangle=1/2bh

A=1/2(4x3)

A=1/2(12)

A=6

Now we can add the three areas together and get the total area:

3+33+6=42 ft

I hope this helps:)

Answer 2

42ft

Explanation:

Area of a triangle = 1/2 * base * height

So that little triangle section:

1/2 * 2 * 3 = 1/2 * 6 = 3

Now we do the rectangle Section:

Area of a rectangle = length * width

So that rectangle is 3 * 7 = 21

If you eliminate those two shapes, you are left with a trapezoid.

Area of a trapezoid is 1/2 * (base 1 + base 2) * height

Base 1 is 3 which is the width of the rectangle.

Base 2 is the 6.

The height is the given 11 feet subtracted by the 7 feet from the length of the rectangle which is 4.

Plug all this in to the formula you get 1/2 * (6 + 3) * 4 = 1/2 * 9 * 4 = 1/2 * 36 = 18.

Now add all of your areas together;

21 + 3 + 18 = 24 + 18 = 42