Answer:
33m/s to the west
Step-by-step explanation:
To describe the motion of Jackie you use the simple sum of velocities in a classical frame of reference. First of all you compute the speed of Jackie measured by an observer at rest. This velocity is the difference between the velocity of the bus and the velocity of Jackie because their motion are opposite.
![v_J'=v_B-v_J](https://img.qammunity.org/2021/formulas/physics/middle-school/epv3v9obu0dvg5v4yli89lto35s3rdviu9.png)
v'J: velocity of Jackie as seen by an observer at rest
vJ: velocity of Jackie = 2m/s
vB: Bus velocity = 20m/s
By replacing you obtain:
= 18m/s
Now, due to the semi-truck is traveling in the same direction of Jackie, you sum this velocities, in order to calculate the velocity of Jackie as seen by the driver in the semi-truck:
![v_J''=v_J'+v_s=18m/s+15m/s=33m/s](https://img.qammunity.org/2021/formulas/physics/middle-school/n5wuxlkylcw1f9o0ipvvwq1xehg85gzb0x.png)
hence, the driver of semi-truck sees that Jackie is moving with a velocity of 33m/s to the west