Question

the labels of bottles that contain barium hydroxide, hydrochloric acid and sodium carbonate had fallen off. When the contents of the bottle A were mixed with B's Contents, a white precipitate formed, A with C yielded a gas and B with C gave heat. Identify A,B,C and write molecular and net ionic equations for the chemical changes observed.

Answer 1

Bottle A contains barium hydroxide, Bottle B contains hydrochloric acid, and Bottle C contains sodium carbonate. When combined, they form a white precipitate in one case, release a gas in another case, and give off heat in the last case.

Step-by-step explanation:

The bottles contain:

1. Bottle A: Barium hydroxide (Ba(OH)2)
2. Bottle B: Hydrochloric acid (HCl)
3. Bottle C: Sodium carbonate (Na2CO3)

The chemical changes observed are:

1. A + B: Formation of a white precipitate (BaSO4) - Molecular equation: Ba(OH)2(aq) + HCl(aq) → BaCl2(aq) + H2O(l) + CO2(g)
2. A + C: Release of a gas (CO2) - Molecular equation: Ba(OH)2(aq) + Na2CO3(aq) → 2NaOH(aq) + BaCO3(s)
3. B + C: Release of heat - Molecular equation: HCl(aq) + Na2CO3(aq) → 2NaCl(aq) + H2O(l) + CO2(g)

Answer 2

Answer:A is SODIUM BICARBONATE,

B is BARIUM HYDROXIDE and

C= HYDROCHLORIC ACID

Step-by-step explanation:

Given Hydrochloric acid, Sodium Carbonate and Barium Chloride.

When A reacts C, a gas is formed. and we know that hydrochloric acid reacts with a carbonate to give a gas.

also Given that A reacts with B to give a white precipitate gives a conclusion that A and B must be a barium hydroxide or Sodium Carbonate therefore means that C must contains HCL

So we are left with Barium hydroxide and Sodium Carbonate which when they react together gives a white precipitate is formed

Reacting Sodium carbonate witrh Hydrochloric acid gives

A + C--- GAS

Molecular equation

Na2co3 (aq) +2HCl(aq)---2NaCl(aq)+ CO(g)+H20 (l)

Net Ionic equation

`CO^(2)`3(aq) +2H+(aq) -- C02(g) +H2O(l)

When Barium hydroxide reacts with Hydrochloric acis, neutralization occurs and heat is released

B+C---------.> Heat

Molecular Equation

Ba(OH)2 + 2HCl(aq)--- BaCl2 +2H2(l)

Ionic Equation

OH- (aq) +H+(aq)----H20(l)

Therefore A is SODIUM BICARBONATE,

B is BARIUM HYDROXIDE and

C= HYDROCHLORIC ACID