Question

A bag contains only red, green, brown and yellow marbles.

The probabilities of selecting each colour are shown below.
Red = 6x
Green = 2x
Brown = x
Yellow = 4x
Find the probability of selecting a brown marble.

Answer 1

The probability of selecting a brown marble from the bag can be found by dividing the number of brown marbles by the total number of marbles in the bag, which is 1/13.

Step-by-step explanation:

The probability of selecting a brown marble can be found by dividing the number of brown marbles by the total number of marbles in the bag. Since the bag contains four different colors of marbles, the total number of marbles is 6x + 2x + x + 4x = 13x. The number of brown marbles is x. So, the probability of selecting a brown marble is:

P(Brown) = x / (6x + 2x + x + 4x) = x / 13x = 1/13

Answer 2

To find the probability of selecting a brown marble, sum the total probability for all marble colors, solve for x, and then use the value of x to get the probability for brown which is 1/13.

Step-by-step explanation:

The question involves calculating the probability of selecting a marble of a certain color from a bag containing marbles of different colors, each with a different probability of being chosen. In this particular problem, we are given that the probabilities of selecting red, green, brown, and yellow marbles are 6x, 2x, x, and 4x, respectively.

Since these are the only colors in the bag, their probabilities must add up to 1 (the total probability), so:

6x + 2x + x + 4x = 1

Summing the multiples of x, we get:

13x = 1

Solving for x gives:

x = 1/13

We can now find the probability of selecting a brown marble, which is just x:

Probability of brown = x = 1/13.