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A charge of 9.0 x 10-5C is placed in an electric field with a strength of 4.0 x 104 N. What is the electrical force acting

on the charge?

User JJ Zabkar
by
5.6k points

1 Answer

3 votes

Answer:

3.6 N

Step-by-step explanation:

E=F/q

so

F=qxE

F= 9x10^-5x4x10^4

F= 3.6 N

User Strangfeld
by
5.7k points