What is the value of n when (9)^2n-1 = (27)^n+2

asked Oct 10, 2021 203k views

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$9^(2n-1) = 27^(n+2) \\ ( {3}^(2) ) ^(2n - 1) = ( {3}^(3) )^( n + 2) \\ {3}^(4n - 2) = {3}^(3n + 6) \\ 4n - 2 = 3n + 6 \\ 4n - 3n = 6 + 2 \\ n = 8$

Answer: n=8

TheZiki answered Oct 16, 2021

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