Given:
In the given triangle ΔABC,
AB = 9 unit
AC = 2 unit
To find the value of ∠ABC.
Formula
From trigonometric ratio we get,
![sin \theta = (opposite)/(hypotenuse)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/5lf7ap12n4niurp3501lwjkg94qfvfitv0.png)
Let us take, ∠ABC =
![\theta](https://img.qammunity.org/2021/formulas/mathematics/middle-school/xa55iai8ybj0afnpxzra0ba7b2i6zcastf.png)
With respect
, AC is the opposite side and AB is the hypotenuse.
So,
![sin \theta = (AC)/(AB)](https://img.qammunity.org/2021/formulas/mathematics/college/1xtqkwx3grpjqa5utct85ot2z81ys61xzc.png)
or,
=
![(2)/(9)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/jktznck182tnm6caow67cec9mn3il2bara.png)
or,
![\theta = sin^(-1) ((2)/(9) )](https://img.qammunity.org/2021/formulas/mathematics/college/e6ig8ptj4jn3y6haq40esg9xblto5ynoi6.png)
or,
![\theta= 12.84^\circ](https://img.qammunity.org/2021/formulas/mathematics/college/dx3oc154jsn0l3zdbewl0ph9bpbjikj6u4.png)
Hence,
The value of ∠ABC is 12.84°.