Question

To introduce you to the concept of escape velocity for a rocket. The escape velocity is defined to be the minimum speed with which an object of mass mmm must move to escape from the gravitational attraction of a much larger body, such as a planet of total mass MMM. The escape velocity is a function of the distance of the object from the center of the planet RRR, but unless otherwise specified this distance is taken to be the radius of the planet because it addresses the question "How fast does my rocket have to go to escape from the surface of the planet?"

Answer 1

11.206 km/s

Explanation: to leave the surface of the earth, you velocity Ve must be;

Escape velocity Ve = (2gRe)^0.5

Where g = acceleration due to gravity 9.81 m/s^2

Re = earth's radius 6400 km = 6.4x10^6

Ve = (2 x 9.81 x 6.4 x 10^6)^0.5

Ve = (125568000)^0.5

Ve = 11205.7 m/s

= 11.206 km/s