Question

Two speakers are placed 500 meters away from each other. A person stands right in the middle of the two speakers. One of the speakers sends a sound wave traveling at 343m/s towards the person standing in the middle and the other speaker sends a sound wave traveling at 342m/s. How long after the person in the middle hears the first sound wave will he hear the second wave ( ) (please answer the question with unit of seconds)

Answer 1

the second wave will be heard at
`2*10^(-3) \ sec` after the first sound wave.

Step-by-step explanation:

Given that:

two speakers are placed 500 meters away from each other and a person is standing in the middle;

that implies that the distance of the speed of the wave travelling is divided into two equal which is 250 m

Now; from the first speaker, time to reach sound wave is;

`t_1 = (250)/(v_1)`

`t_1 = (250)/(343)`

`t_1 = 0.728 \ sec`

Also from the second speaker; time to reach sound wave is;

`t_2 = (250)/(v_2)`

`t_2 = (250)/(342)`

`t_2 =0.730 \ sec`

`t_2 - t_1 = (0.730 - 0.728 )\ sec`

`= 0 .002 \ sec\\\\= 2*10^(-3) \ sec`

Thus, the second wave will be heard at
`2*10^(-3) \ sec` after the first sound wave.