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Write an equation in slope-intercept form that is parallel to y - 5x = 10 and passes through the point (2, -4).

User Dawidklos
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2 Answers

7 votes
7 votes
  • y-5x=10
  • y=5x+10

Slope:-

  • m=5

Parallel lines have equal slope

  • passes through (2,-4)

Equation in point slope form

  • y-y1=m(x-x1)
  • y+4=5(x-2)
  • y+4=5x-10
  • y=5x-14
User Simon Bingham
by
2.7k points
9 votes
9 votes

Answer:

y = 5x - 14

Explanation:

*Parallel lines have the same slopes*

Rewrite your equation to slope-intercept form: y = mx + b

y = mx + b

  • m = slope
  • b = y-intercept (when x = 0)

y - 5x = 10 <== add 5x to both sides

+ 5x + 5x

y = 5x + 10

The slope of the line that is parallel to this line is 5.

We need to find the y-intercept (b) for the parallel line using (2, -4):

y = 5x + b <== substitue 2 for x and -4 for y

-4 = 5(2) + b

-4 = 10 + b <== subtract 10 from both sides to isolate b

-10 -10

-14 = b

y = 5x + b changes to y = 5x - 14

Hope this helps!

Write an equation in slope-intercept form that is parallel to y - 5x = 10 and passes-example-1
User Zettt
by
2.7k points