Answer:
31.36 KJ/mol
Step-by-step explanation:
mass of the liquid = 74.0 g
heat of vaporization = 21.40 kJ/mol
constant boiling point temperature = 24.09 °C
heat required to vaporize 74.0g = heat of vaporization × mole
mole of Chloromethane = 74.0 g / 50.49 (g/mol) = 1.466 mol
energy required = 1.466 mol × 21.40 KJ/mol = 31.36 KJ/mol