Question

(11%) Problem 5: A uniform stationary ladder of length L = 2.7 m and mass M = 11 kg leans against a smooth vertical wall, while its bottom legs rest on a rough horizontal floor. The coefficient of static friction between floor and ladder is μ = 0.45. The ladder makes an angle θ = 51° with respect to the floor. A painter of mass 8M stands on the ladder a distance d from its base. show answer No Attempt 33% Part (a) Find the magnitude of the normal force N, in newtons, exerted by the floor on the ladder.

Answer 1

970.2 N

Step-by-step explanation:

We are given that

Length of ladder=2.7 m

Mass,M=11 kg

Coefficient of friction=
`\mu=0.45`

`\theta=51^(\circ)`

Mass of painter=8M

Distance from base=d

We have to find the magnitude of the normal force exerted by the floor on the ladder.

Normal force exerted by floor on the ladder=
`mg+8mg=9mg`

Where
`g=9.8m/s^2`

Normal force exerted by floor on the ladder=
`9* 11* 9.8=970.2N`