Question

The following code accomplishes which of the tasks written below? Assume list is an int array that stores positive int values only.int foo = list[0];for (int j =1 ; j < list.length; j++)if (list[j] > foo)foo = list[j];Group of answer choicesit stores the largest value in list (the maximum) in fooit stores the smallest value in list (the minimum) in fooit stores every value in list, one at a time, in foo, until the loop terminatesit counts the number of elements in list that are greater than foo

Answer 1

it stores the largest value in list (the maximum) in foo

Step-by-step explanation:

Initially foo is assigned as the first element of the list

Inside the loop, every element in the list will be compared with foo, starting from the second element. If an element is greater than foo, the new value of the foo will be that element. At the end of the loop, foo will be equal to the largest element in the list.