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42 votes
Find the slope of the line that is parallel and perpendicular to the following equation.

-4x - 4y = -2

User Simon Dowdeswell
by
2.6k points

2 Answers

14 votes
14 votes

Answer:

Parallel line:

-1

Perpendicular line:

1

Explanation:

Let's simplify first!

-4x-4y=-2

-4x=-2+4y

4y=-4x+2

y=-x+0.5

For a parallel line, the slope should be the same

Therefore...

Slope=1

For a perpendicular line, the slope should be the negative reciprocal of the original.

Therefore...

Slope=-(-
(1)/(1))

=1

Hope this helps! :D

User Ahjmorton
by
2.8k points
14 votes
14 votes

Answer:

Slope of the line that is parallel: -1

Slope of the line that is perpendicular: 1

Explanation:

For the parallel line:

Rewrite your equation to slope-intercept form: y = mx + b

y = mx + b

  • m = slope
  • b = y-intercept (when x = 0)

-4x - 4y = -2 <== add 4x to both sides

+4x +4x

-4y = 4x - 2 <== divide both sides by -4

/-4 /-4

y = -x + 1/2

The slope of the line that is parallel to this line is -1 (invisible 1 in front of x).

For the perpendicular line:

*Perpendicular lines have negative reciprocals*

Steps:

1. Take your original slope (-1)

2. Flip it (-1/1)

3. Change the sign (1)

For a slope of -1, the reciprocal would be: 1

Hope this helps!

User MerklT
by
3.0k points