1 Answer

Theglauber · Answer 1 · 2021-11-23T05:45:14+0000

Answer:

$f(x)=x^2+4\\g(x)=4x$

$(f+g)(x)=x^2+4+4x\\(f+g)(x)=x^2+4x+4$

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$(f-g)(x)=x^2+4-(4x)\\(f-g)(x)=x^2+4-4x\\(f-g)(x)=x^2-4x+4\\$

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$(f*g)(x)=(x^2+4)(4x)\\(f*g)(x)=4x^3+16x$

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$((f)/(g))(x)= (x^2+4)/(4x) \\$

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