Question

A metal salt with the formula MSO4 crystallizes from water to form a solid with the composition MSO4⋅3H2O. At 298 K, the equilibrium vapor pressure of water above this solid is 14.7 Torr. MSO4⋅3H2O(s)↽−−⇀MSO4(s)+3H2O(g) What is the value of ΔG for the reaction when the vapor pressure of water is 14.7 Torr?

Answer 1

To find the value of ΔG for the reaction MSO4⋅3H2O(s)↽−−⇀MSO4(s)+3H2O(g) at the given vapor pressure of water, use the equation ΔG = -RTln(K), where ΔG is the change in Gibbs free energy, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.

Step-by-step explanation:

The reaction can be represented as: MSO4·3H2O(s) <--> MSO4(s) + 3H2O(g)

The equilibrium vapor pressure of water above the solid is 14.7 Torr.

Since we are given the equilibrium condition, we can use the equation ΔG = -RTln(K), where ΔG is the change in Gibbs free energy, R is the gas constant, T is the temperature in Kelvin, and K is the equilibrium constant.

By plugging in the given values, we can calculate the value of ΔG at the equilibrium condition.