Answer:
def string_with_most_the(string_list):
index = 0
count = []
max_length = 0
for i in range(len(string_list)):
s1 = string_list[i].lower()
count.append(s1.count("the"))
if count[i] > max_length:
max_length = count[i]
index = i
return string_list[index]
Step-by-step explanation:
Create a function called string_with_most_the that takes one parameter, string_list
Inside the function:
Initialize the variables
Initialize a for loop that iterates through string_list
Set the lower case version of the strings in string list to s1
Count how many "the" each string in string_list contain and put the counts in the count list
If any string has more "the" than the previous one, set its count as new maximum, and update its index
When the loop is done, return the string that has maximum number of "the", string_list[index]