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The stopping distance of a car is modeled by the function d = 0.05r(r + 2) where d is the stopping distance of the car measured in feet and r is the speed of the car in miles per hour. If skid marks left on the road are 75 feet long, how fast was the car traveling?

User Charlez
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Answer:

The car was moving approximately at a speed of 37.74 miles per hour.

Explanation:

We are given the following in the question:

The stopping distance of a car is given by


d = 0.05r(r + 2)

where d is the stopping distance in feet and r is speed of the car in miles per hour.

The stopping distance is 75 feet, we have to find the speed of the car,

Putting d = 75 in the equation, we get,


75 = 0.05r(r + 2)\\r^2 + 2r = 1500\\r^2 + 2r-1500 = 0\\\\r =(-2\pm √(4-(4)(1)(-1500)))/(2)\\\\r\approx -39.74,37.74

Thus, the car was moving approximately at a speed of 37.74 miles per hour.