Question

A dumbbell-shaped object is composed by two equal masses, m, connected by a rod of negligible mass and length r. If I_1 is the moment of inertia of this object with respect to an axis passing through the center of the rod and perpendicular to it and l_2 is the moment of inertia with respect to an axis passing through one of the masses, it follows that l_1 = l_2. l_l > l_2. l_2 > l_1

Answer 1

Answer:
`I_2>I_1`

Step-by-step explanation:

Given

Shape of the object is dumbbell shaped

Moment of Inertia w.r.t an axis passing through center and perpendicular to it

`I_1=m((r)/(2))^2+m((r)/(2))^2`

`I_1=(mr^2)/(2)`

For the axis which passes through one of the masses

`I_2=mr^2`

so
`I_2>I_1`