Answer:
2.5 mg
Explanation:
We are given that
A=Initial amount=10 mg
Half life,h=8 days
We have to find the mass of radioactive isotope remains after 16 days.
t=16 days
We know that the amount of radioactive isotope after t days is given by
![P(t)=A(1(1)/(2)^{(t)/(h))](https://img.qammunity.org/2021/formulas/mathematics/high-school/umgjg5fmyjexr2xdo94tr7t5a8dm11ljdc.png)
Using the formula
![P(t)=10((1)/(2)^{(16)/(8)})](https://img.qammunity.org/2021/formulas/mathematics/high-school/ubaafex1hsndp4x4g1nt74iov5d0f4mq10.png)
![P(t)=10* ((1)/(2))^2](https://img.qammunity.org/2021/formulas/mathematics/high-school/sr92deu059bwual41gidhgc653v95aoen9.png)
![P(t)=2.5 mg](https://img.qammunity.org/2021/formulas/mathematics/high-school/wpe1g7rdvgzei3b8zf4ppbhcwow4m9mt7q.png)