Question

A circular specimen of MgO is loaded in three-point bending. Calculate the minimum possible radius of the specimen without fracture, given that: the applied load is 5560 N the flexural strength is 105 MPa the separation between the supports is 45 mm Input your answer as X.XX mm, but without the unit of mm.

Answer 1

radius = 9.1 ×
`10^(-3)` m

Step-by-step explanation:

given data

applied load = 5560 N

flexural strength = 105 MPa

separation between the support = 45 mm

solution

we apply here minimum radius formula that is

radius =
`\sqrt[3]{(FL)/(\sigma \pi)}` .................1

here F is applied load and is length

put here value and we get

radius =
`\sqrt[3]{(5560* 45* 10^(-3))/(105 * 10^6 \pi)}`

solve it we get

radius = 9.1 ×
`10^(-3)` m