Question

Young's experiment is performed with light of wavelength 502 nmnm from excited helium atoms. Fringes are measured carefully on a screen 1.40 mm away from the double slit, and the center of the 20th fringe (not counting the central bright fringe) is found to be 10.4 mmmm from the center of the central bright fringe. Part A What is the separation of the two slits? dd = nothing mmmm SubmitRequest Answer Provide Feedback

Answer 1

Step-by-step explanation:

wavelength of light λ = 502 x 10⁻⁹ m /s

screen distance D = 1.4 m

Slit separation d = ?

position of n the separation is given by the formula

x = n Dλ / d , n is order of fringe , x = distance of n th fringe

10.4 x 10⁻³ = 20 x 1.4 x 502 x 10⁻⁹ / d

d = 20 x 1.4 x 502 x 10⁻⁹ / 10.4 x 10⁻³

= 1351.54 x 10⁻⁶

= 1.35 x 10⁻³ m

1.35 mm.