Question

public class Test { public static void main(String[] args) { try { method(); System.out.println("After the method call"); } catch (ArithmeticException ex) { System.out.println("ArithmeticException"); } catch (RuntimeException ex) { System.out.println("RuntimeException"); } catch (Exception e) { System.out.println("Exception"); } } static void method() throws Exception { System.out.println(1 / 0); } }

Answer 1

"ArithmeticException" is the correct answer for the above question.

Step-by-step explanation:

Missing Information : The above question does not hold that "what is the output of the program".

• The above question has a class that holds the two functions one function is the main function which calls the other function in a try-catch block.
• The method function holds one run time exception which is 1/0 which is an arithmetic exception.
• It can be handle by the help of an arithmetic class object which is defined in the first catch block.
• Hence the print function of this catch is executed and prints "ArithmeticException".