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5. How many moles are in 58.6 L of Nitrogen gas (N.) at STP?
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5. How many moles are in 58.6 L of Nitrogen gas (N.) at STP?

User Baker
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3 votes

Answer:

2.6166 moles

Step-by-step explanation:

stp means: T=273k p=101.3kpa

R= 8.31(constant) v=58.6

using the ideal gas law; pv=nRt

101.3 x 58.6 = n x 8.31 x 273

n= (101.3 x 58.6)\(8.31 x 273)

n= 2.6166moles

User Mofi
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