Question

A 15 A current is directed along the positive x-axis and perpendicular to a uniform magnetic field. The conductor experiences a magnetic force per unit length of 0.20 N/m in the negative y direction. Calculate the magnitude of the magnetic field in the region through which the current passes. Answer in units of T.

Answer 1

The magnitude of magnetic field in the region through the current passes is 0.0133 T

Step-by-step explanation:

Given:

Current
`I = 15` A

Force per unit length
`(F)/(l) = 0.20 (N)/(m)`

The magnetic force on current carrying conductor is given by,

`F = IlB`

For finding the magnetic field,

`B = (F)/(Il)`

`B = (0.20)/(15)`

`B = 0.0133` T

Therefore, the magnitude of magnetic field in the region through the current passes is 0.0133 T