Answer:
357 mJ
Step-by-step explanation:
Parameters given:
Number of turns, N = 113
Radius, r = 2.71 cm = 0.0271 m
Resistance connected to coil, R = 10.3 ohms
Time interval, dt = 0.153 s
Change in magnetic field, dB = 0 - 0.441 T = - 0.441 T
First, we need to find the induced EMF in the coil. It is given as:
V = - (N * A * dB)/dt
A = area of coil = pi * r² = 3.142 * 0.0271² = 0.0023 m²
Therefore:
V = - (113 * 0.0023 * - 0.441) / 0.153
V = 0.75 V
Electrical energy dissipated in the resistor is given as:
E = V² / (R * t)
Where t is the time (0.153 secs)
E = (0.75²) / (10.3 * 0.153)
E = 0.357 J = 357 mJ
The energy dissipated in the resistor is 357 mJ