- The time period is independent of the mass.
- The period is proportional to the square root of the length of the wire.
Step-by-step explanation:
The time period of the simple pendulum that consists of a point mass suspended by a weightless, rigid wire in a uniform gravitation field is given by :
![T=2\pi \sqrt{(l)/(g)}](https://img.qammunity.org/2021/formulas/physics/college/h96qbyfu133gqyidc8e5lx2jif62xv72il.png)
l is length of simple pendulum
g is acceleration due to gravity.
It is clear that, the time period is independent of the mass. Also, the period is proportional to the square root of the length of the wire.
Hence, the correct options are (B) and (F).