Question

Water flows with an average speed of 6.5 ft/s in a rectangular channel having a width of 5 ft The depth of the water is 2 ft.

Part A

Determine the specific energy.

Express your answer to three significant figures and include the appropriate units.

E =
SubmitRequest Answer

Part B

Determine the alternate depth that provides the same specific energy for the same volumetric flow.

Express your answer to three significant figures and include the appropriate units.

Answer 1

specific energy = 2.65 ft

y2 = 1.48 ft

Step-by-step explanation:

given data

average speed v = 6.5 ft/s

width = 5 ft

depth of the water y = 2 ft

solution

we get here specific energy that is express as

specific energy = y +
`(v^2)/(2g)` ...............1

put here value and we get

specific energy =
`2 + (6.5^2)/(2* 9.8* 3.281)`

specific energy = 2.65 ft

and

alternate depth is

y2 =
`(y1)/(2) * (-1+√(1+8Fr^2))`

and

here Fr² =
`(v1)/(√(gy)) = (6.5)/(√(32.8* 2))`

Fr² = 0.8025

put here value and we get

y2 =
`(2)/(2) * (-1+√(1+8* 0.8025^2))`

y2 = 1.48 ft