Question

In simplest radical form, what are the solutions to the quadratic equation 0 = -3x2 - 4x + 5?

Quadratic formula: x = =
--D# 6² - 4ac
x= - 24/19
© x= - 242/19
© x= 2Y15
x= 2:2/19
Mark this and return

Answer 1

Simplest radical form for the solutions:
`x=(-2+/-\,√(19) )/(3)`

Explanation:

The solutions to the quadratic equation (
`-3x^2-4x+5`) is given by applying the quadratic formula with values:
`a=-3,\,\,b=-4,\,\,and\,\,c=5`

Which becomes:

`x=(-b+/-\,√(b^2-4ac) )/(2\,a) \\x=(4+/-\,√((-4)^2-4(-3)(5)) )/(2\,(-3)) \\x=(4+/-\,√(16+60) )/(-6) \\x=(4+/-\,√(72) )/(-6) \\x=(2*2+/-\,2√(19) )/(-3*2) \\x=(-2+/-\,√(19) )/(3)`